Question

2. Consider the network described in the table below. Immediate Predecessor(s) Activity J K L M N O Р Pessimistic 15 9 10 3 9

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Answer #1

Mean and variance values are given below.

Task O M P Te Var^0.5 Variance
J 8 10 15 10.5 1.166667 1.361111
K 7 8 9 8 0.333333 0.111111
L 5 6 10 6.5 0.833333 0.694444
M 3 3 3 3 0 0
N 1 5 9 5 1.333333 1.777778
O 4 7 10 7 1 1
P 3 8 10 7.5 1.166667 1.361111
Activity ES EF LS LF Slack
J 0 10.5 0 10.5 0
K 0 8 5.5 13.5 5.5
L 10.5 17 12 18.5 1.5
M 10.5 13.5 10.5 13.5 0
N 13.5 18.5 13.5 18.5 0
O 13.5 20.5 19 26 5.5
P 18.5 26 18.5 26

کنم 10.5 3 مه 8

Critical path is JMKP with duration 26.

Variance of critical path = 2.8333

SD of critical path = (2.8333)^0.5 =1.6832

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