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a Compute the upper and lower limits for the following data at a 95% CI, when M1 = 20, M2 = 15, t-table value = 2.145, and S(
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Answer #1

M1 = 20 , M2 = 15 , So ( M1-M2 ) = 20-15 = 5

Confidence interval is given by ,

Lower bound = (M_1 - M_2 )- t*S_{(M1-M2)} = 5 - (2.145*1.34)

Lower bound = 2.1257

Upper bound = (M_1 - M_2 )+ t*S_{(M1-M2)} = 5 + (2.145*1.34)

Upper bound = 7.8743

Answer : C . UL : 7.87 ; LL : 2.13

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