Question

What is the impedance, magnitude, and angle for the following AC circuit: AC battery of 10V and 0.5 hz when a 0.1 Farad capacitor and a 10ohm resistor are in parallel series.

- х 50 25 Current (Amps) 0 -25 -50 215 216 217 218 219 Time (s) x 25 Voltage (V) 0 WWW -25 215 216 217 218 219 imation speed limit reached. Simulation speed reduced to 73% normal!

Answer 1

Dear Student,

Here the concept hides in the current through the capacitor always produces a 90 degree phase difference with the current through the resistance for same source of voltage...

After finding the total impedance Zrc the figure of impedance with the components in Complex plane (Argend plane) has been drawn..

Now follow the step by step details solution..

Happy to help you.

AC ( SV=lov 1 IR ) Voltage, V = lov frequency of = 0.5 Hz Capacitance, C=0.1F Resistance, R=102 II. @=0.FR=100 Sarce R² we a It THRZWICE : Impedance due to capacitors - Capacitive resistance we 1 we enfe Zre Xc 10 Vq R 1+R²W2C2 20*0.5% oil - 3.1832 It Total impedence is Zre then + - ZRC R te R iwe @[ ZRC k tiwe Xe = we 1 tj Rue R R(1-jRwe) R – j R² we (1 + 1 Rwe) (1-jRwe) 1 + R² w2e² CR we (1+R²whee It jRwe R ZRC j 1 + R²w2e2 ZRC = (0.92 - 12.89 R Now, froom w R2 +(3070)? R2 & w2e2 2 2ке. 19 +2.740) 163 +12400-5201 . Zrc=3.033 = 3.033 10-01 from ( Angle, o = tant (- w RC) = tant (20.5 x 100 = 72:34°