A torque of 2.00 Nm acts on a cylindrical which has a moment of inertia 0...

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Answer 1

Answer #1

Torque = moment of inertia * angular acceleration

2 = 0.25 * alpha

alpha = 8 rad/s2

w = alpha * t

w = 8 *10 = 80 rad/s (a)

Centripetal force = friction force

mv^2/r = umg

u = v^2/rg

u = 12.1*12.1/30*9.8

u = 0.50 (b)

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Answer 2

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