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Question 16 (6 points) A 75-N-m torque acts on a wheel with a moment of inertia 275 kg•m². If the wheel starts from rest, how
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Answer #1

Torque, Ꞇ = 75 Nm

Moment of inertia, I = 275 kgm2

Initial angular speed, ωi = 0 rad/s

Number of revolutions, n = 2

If α is the angular acceleration then

Angular acceleration, α = Ꞇ/I = 75/275 = 0.273 rad/s2

Using the equation, θ = ωi t + ½ α t2

But, θ = 2πn

2πn = ½ α t2

2 x 3.14 x 2 = ½ x 0.273 x t2

t = 9.6 s

time required to make 2 revolutions is

(d) : 9.6 s

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