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An armature controlled d.c motor is supplied in series with a resistance from a 24 d.c. supply. The motor takes a current of 5A on stalling and the stalling torque being 0.915 N-m. The motor runs at 1000rpm taking a current of 1 A. The moment of inertia and coefficient of viscous friction are 4 x 10^3 kg-m^2 and 1.5 x 10^-3 Nm/(rad/sec) respectively. Determine the transfer function of the motor

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Answer #1

R wwwy ti + to V V=24 ә 9 81 i=v-eb R e = kw i=v-kbw 6 Ta Ktia By ( V - Kow) = RIY -haken we T = R 3 KTV .-k kb w Ш R R i = 5192 + K (loe ) Ч. – Ч. 8 J1 О. 183 в •183) ka = 19 2Х3 100 Г E = |put. Kb=K = 0.183 R=4.8 in equation T = 00183 v 0.183 W 4.8 4.8 T = 0.038125 V- 0038125 W Take Laplace Tos) 00038125 VIS) - 0

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