In C

Code provided:
#include <stdio.h>
int recursive_sequence(int n)
{
//type your code here
}
int main()
{
int number;
scanf("%d", &number);
printf("recursive_sequence(%d) = %d",number,
recursive_sequence(number));
return 0;
}
#include <stdio.h>
int recursive_sequence(int n){
if(n==0){
return 0;
}
else if(n==1){
return 1;
}
else{
return 2*recursive_sequence(n-2) + recursive_sequence(n-1);
}
}
int main()
{
int number;
scanf("%d", &number);
printf("recursive_sequence(%d) = %d",number, recursive_sequence(number));
return 0;
}

In C Code provided: #include <stdio.h> int recursive_sequence(int n) { //type your code here } int...
i need flowchart for the following c code #include <stdio.h> int main() { int n, i, sum = 0; printf("Enter an integer: "); scanf("%d",&n); i = 1; while ( i <=n ) { sum += i; ++i; } printf("Sum = %d",sum); return 0; }
Solve using C programming
3. lf you are given this code. #include <stdio.h> int main() int var1, var2; int sum; printf("Enter number 1:\n "); scanf("%d",&var1); printf("Enter number 2:In ); scanf("%d",&var2); sum-var1+var2; printf ("Vnsum of two entered numbers : %d", //printf ("Output: %d", res); sum); return e; Modify this code by creating a function called "addition". Make the arguments of the functions numberl and number 2. Add the two values in the function. Return a value called "result". Print "result" in...
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Convert the below C code to basic MIPS. Please leave comments for explanation #include <stdio.h> int main(void) { printf("Insert two numbers\n"); int a,b; scanf("%d",&a); scanf("%d",&b); a=a<<2; b=b<<2; printf("%d&%d\n",a,b); return 0; }
Convert the below C code to basic MIPS. Leave comments for explanation please #include <stdio.h> int main(void) { printf("Insert two numbers\n"); int a,b,c; scanf("%d",&a); scanf("%d",&b); c=a|b; printf("%d|%d=%d\n",a,b,c); return 0; }
Fix the errors in C code #include <stdio.h> #include <stdlib.h> void insertAt(int *, int); void Delete(int *); void replaceAt(int *, int, int); int isEmpty(int *, int); int isFull(int *, int); void removeAt(int *, int); void printList(int *, int); int main() { int *a; int arraySize=0,l=0,loc=0; int choice; while(1) { printf("\n Main Menu"); printf("\n 1.Create list\n 2.Insert element at particular position\n 3.Delete list.\n4. Remove an element at given position \n 5.Replace an element at given position\n 6. Check the size of...
Translate the following C program to Pep/9 assembly language. #include <stdio.h> int main() { int number; scanf("%d", &number); if (number % 2 == 0) { printf("Even\n"); } else { printf("Odd\n"); } return 0; }
Do you have a flowgorithim flow chart for this code? #include <stdio.h> int main() { int num,i=0,sum=0; float average; int customerNumbers[num]; int customerSales[num]; printf("How many customers do you want to track?\n"); scanf("%d",&num); while(i<num) { printf("Enter the customer number. "); scanf("%d",&customerNumbers[i]); printf("Enter the sales for the customer "); scanf("%d",&customerSales[i]); i++; } printf("Sales for the Customer"); printf("\nCustomer Customer"); printf("\nNumber Sales"); for(i=0;i<num;i++) { printf("\n %d \t %d",customerNumbers[i], customerSales[i]); sum=sum+customerSales[i]; } average=(int)sum/num; printf("\n Total sales are $%d",sum); printf("\n Average sales are $%.2f",average); printf("\n --------------------------------------------");...
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The following function is_prime() is not a very efficient prime number test: #include <stdio.h> int is_prime(int n) { int d; for (d = 2; d < n; d++) { if (!(n % d)) return 0; } return 1; } int main() { if (is_prime(7)) printf("Seven is Prime!\n"); return 0; } It is unnecessary to divide n by all numbers between 2 and n - 1 to determine if n is prime. Only divisors up to and including need to be...