Question

Determine the degree of freedom (df):

K=
df = K – 1 =

Find out the probability (p-value)

The probability is:

Determine the significance:

The level of significance is:

Conclusion:

My experiment

□ agrees

□ disagrees with Mendel’s law of segregation.

O-E O-E) O-EYE 1.1 1.21 4.73x103 Observed Expected Fast Plants Phenotype number for Exp 1. Exp. 1 Purple stem green 255.9 257 leaves Purple stem yellow 185.3 188 leaves Green stem green leaves 79 185.3 Green stem yellow 128.4 |31 leaves 12.7 17.29 10.085 1-6.3 39.69 6.76 10.47 10.24 12.6 1455 Total number of plants 455 10.80 Expected O-E O-E) Observed horfor O-E) E Evn 2 2. Determine the degree of freedom (df): K= df=K-1= 3. Find out the probability (p-value) from Table 14.1: Chap The probability is: 4. Determine the significance: The level of significance is: 5. Conclusion: My experiment agrees disagrees with Mendel's law of segregation. State how you came to this conclusion.

please show work, so i can follow along and understand

Answer 1

ANSWER :-

The degree of freedom = (K-1)

= (4-1)

= 3

P-value = The value of the statistical test lies in the range of 0.80 and 0.90 and thus the p-value should be between them. The p-value is less than 0.90 and more than 0.80 and should fall in between them.

The calculated p-value is calculated to be 0.849467 and at the level of significance of 0.05, the p-value is not significant taking into consideration that the p-value is more than 0.05 and hence it can be stated that the results are not significant and thus the null hypothesis is accepted. So, in short it disagrees with the Mendel's law of segregation.

NOTE : Respected Sir/Madam,for any doubts, please prefer communicating through the comment section.