Homework Answers
1)
m = 0.632 g of metal
m = 0.923 g of MCl
a)
%metal = m/total M = 0.632/0.923 *100 = 68.4723%
2)
empirical formula
mol of M = mass/MW = 0.632/154.2 = 0.004098
mol of Cl = mass/MW
mass of Cl = 0.923 -0.632 = 0.291
mol of Cl = mass/MW = 0.291/35.5 = 0.008197
then
ratios
0.008197/0.004098 = 2
then
MCl2 is the empirical formula
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