Question

write the condensed electron configuration:

Re

Re^4+

Re^6+

Re^7+

Answer 1

Atomicnumber of rhenium (Re) = 75 No of electrons present in Re = 75 Electronic configuration of Re = 1522s22p%3:23p 432 3d104p0552 40105p6s24 yl45d5 Electronic configuration of Ret* = 1s 2s 2p 3s 3p 4° 320 4p584d105p684145d3 = 152252 2p 3s 3p 45°3d1" 4p5524705p 4/45d3 Electronic configuration of Re®* = 1s 2s 2p 3s 3p 4:2 3:0 4p5s4d05p4,14581 Electronic configuration of Re* = 1825*2p 3s 3p 48° 32° 4p5s 40:"05p4 yul45d