1mol of H2, 2.0mol of I2, 3mol of HI are injected into 1 Litre flask. What will be the equilibrium concentration of H2, I2, HI at 490^C? The equilibrium constant for the reaction is 45.9.
![Ans Kc - 45.9 H₂ Iz 2 HI - 2 3 initial mole at eluilibrium |-X 3 + 2x 2-x Kc = [HI]2 [H22 Iz usog = (3+2x)? (1-x) (2-x) X = 0](http://img.homeworklib.com/questions/09d13220-2080-11eb-9f2a-15bd8fa038ce.png?x-oss-process=image/resize,w_560)
1mol of H2, 2.0mol of I2, 3mol of HI are injected into 1 Litre flask. What...
The following reaction was performed in a sealed flask at 999 degreesCelsius. H2 (g) + I2 (g) 2 HI (g) Kc = 222. If H2 and I2 are both 0.15 M at equilibrium, what is the concentration of HI at equilibrium?
Suppose that 0.1000 mole each of H2 and I2 are placed in 1.000-L flask, stoppered, and the mixture is heated to 425oC. At equilibrium, the concentration of I2 is found to be 0.0210 M. a) What are the equilibrium concentrations of H2 and HI, respectively? Calculate Kc for the following reaction at 425oC. H2(g) + I2(g) ⇄ 2 HI(g) b) If the initial concentrations of H2 and I2 are 1.000 M each, and the initial concentration of HI is 0.000,...
Suppose a 500.mL flask is filled with 1.7mol of I2 and 0.80mol of HI. The following reaction becomes possible: H2(g)+I2(g) > 2HI(g). The equilibrium constant K for this reaction is 0.142 at the temperature of the flask. Calculate the equilibrium molarity of HI. Round your answer to two decimal places.
A sealed tube initially contains 9.84x10-4mol of H2and 1.38x10-3mol of I2. It is kept at 350C until the reaction H2(g) + I2(g) <=> 2HI (g) comes to equilibrium. At equilibrium 4.73x10-4moles of I2 are present. Calculate the number of moles of H2 and HI at equilibrium and the equilibrium constant Kc for the reaction. (please provide steps on how to approach this problem) I noticed that the system is not initially at equilibrium so i used ICE method to find...
An equilibrium mixture contains 0.950 mol HI, 0.490 mol I2, and 0.290 mol H2 in a 1.00-L flask. What is the equilibrium constant for the following reaction? 2HI(g) H2(g) + I2(g) K = How many moles of I2 must be removed in order to double the number of moles of H2 at equilibrium? mol I2
A flask containing 0.10 atm of H2(g) and excess I2(s) is heated and allowed to reach equilibrium according to the reaction below. The equilibrium constant is 0.25 at this temperature. What is the partial pressure of HI(g) at equilibrium? 2HI(g) --> H2(g) + I2(s) Please help and show work. Thank you
consider the equilibrium reaction of H2 (g) + I2 (g) <-----> 2 HI (g) it has an equilibrium constant Kc = 54.3 at 430°C. if the initial concentration of [HI]0 = 2.000 M. what are the equilibrium concentrations?
The following reaction: H2 (g) + I2 (g) ⇋ 2 HI (g) Has an equilibrium constant of 30.5 under certain conditions. If initial concentrations of reactants and product are: [H2] = 0.100 M; [I2] = 0.100 M; and [HI] = 0.250 M, what will be the equilibrium concentration of HI?
Consider the reaction: H2(g)+I2(g)⇌2HI(g) A reaction mixture in a 3.69 −L flask at 500 K initially contains 0.377 g H2 and 17.93 g I2. At equilibrium, the flask contains 17.72 g HI. Calculate the equilibrium constant at this temperature.
Given the reaction below, H2 (g)+ I2 (g)⇌ 2 HI (g) Kc = 50.5 What was the initial mass of HI (g) placed in a sealed 1.50 L flask which resulted in 0.025 mol of each of H2 (g) and I2 (g) being found in the flask at equilibrium?