Question

2 points 3s The Laplace inverse of F(s)= 52 - 2Ms +3M is Your answer

Answer 1

Solution: Given that FIS) = 35 s? 2MS +3M2 35 FIS) = (52-2M3+M3)+2M2 35 FIS) FIS) (S-M) + Gom)? 3(S-MTM) (S-M)? +(X2M)2 3 (S-M) (S-M)2 + (52m)? (S-M)*+12M)2 + 3M FLS) 82M) + 3 FIS) 3(5-M) S-M)2+(82M) ře (s-M) ²+(129) 2 taking daplace inverse both side we get (2M) f'qF4593= fit) = 3 fi'$ CS-M) 6m)24[remies (SMJ2hVzmi? fit) = 3cu tos (T2M)t + 3 meter or cuēma) + 2+3 LY ve flt) = ot) cos(82M) t t / sin (TEM)t Ő zemer this is required folution Nate en fer eat cos(bt) 29)²+62 ** { copia} = eat sincet)