Question

Question #1: Passive Filters For the filter shown in Figure 1, using PSPICE a) Show your implementation of this circuit using PSPICE b) Plot the Bode Diagram (magnitude plot and phase plot) c) From the result of part b, what is the type of this filter? d) From part b Find Wc1,Wc2,W,, Q, and B 8k12 10 mH 10 nF Figure 1

please use PSPICE and put the solutuin in clear way .

pspice is requird please

Answer 1

Solution: As SPICE Simulation performs all the calculation in terms of Linear frequency i.e in Hertz , we can obtain the result from plots and using relation w =2πf rad/sec we convert the quantities in rad/sec.

The detailed solution is given below -

R1 Vi Vo 8k L1 10m V1 I 1 Vac OVdc C1 10n 0 Circuit schematic using PSPICE

Simulation Settings - bias General Analysis Configuration Files Options Data Collection Probe Window AC sweep Type Analysis type: AC Sweep/Noise O Linear Start Frequency: 1k Logarithmic End Flequency: 50K Decade Total Points: 1000 Options: General Settings Monte Carlo/Worst Case Parametric Sweep Temperature (Sweep) Save Bias Point Load Bias Point ODDDD3 Noise Analysis Enabled Output Voltage: IN Source: Interval: Output File Options Include detailed bias point information for nonlinear controlled sources and semiconductors (OP) OK Cancel Apply Help A.C SWEEP SIMULATION SETTINGS Simulation command to plot the frequency response Bode Plot of Vo Ni

Add Traces Simulation Output Variables Functions or Macros Analog Operators and Functions Analog Digital Voltages Currents Power Frequency VIO) V(C1:1) V[C1:2) VIL1:1) V[L1:2) V(R1:1) V(R1:2) V[V1:+) VIV1:-) VIVO VIVO) V1(C1) V1(L1) V1(R1) V1/V1) V2(C1) V2(L1) V2(R1) V2/V1) Noise (V/Hz) ✓ Alias Names @ ABSU) ARCTANO) ATAN) AVGO) AVGX) COSO DO DBO ENVMAXL) ENVMINI.) EXPO) GO IMG) LOGO) LOG100) MO world MINO PO PWBV) Subcircuit Nodes Add this to trace the phase plot 20 variables listed Full List Trace Expresfion: PIV[VO]/[VI)) ОК Cancel Help Command for simulation of the Phase plot

Date/Time run: 05/14/20 06:53:26 Temperature: 27.0 (A) bias.dat (active) 1000 50d Od -50d -1000 OHz P(V(Vo) /V(Vi)) 10KHZ 20KHZ 30KHZ 40KHZ 50KHz 60KHZ Frequency Date: May 14, 2020 Page 1 Time: 06:54:46 Phase plot obtained using PSPICE

Add Traces Simulation Output Variables Functions or Macros Analog Operators and Functions Analog #O A # 0 Digital Frequency VIO) V[C1:1) V(C1:2) V(L1:1) V[L1:2) V[R1:1) V(R1:2) V[V1:+) VIV1:-) VIVO VIVO) V1(C1) V1(L1) V1(R1) V1[V1) V2(C1) Voltages Currents Power Noise (V/Hz) ✓ Alias Names Subcircuit Nodes ABSO ARCTANO ATANO AVGO) AVGX) COSO) DO DB ENVMAXI) ENVMINI) EXP() V2(R1) V2/V1) V2L1 Add this to plot magnitude plot of vo/vi GO B 20 variables listed IMG) LOGO LOG101) MO MAXO Full List Irace Expressid: ABS(VIVO)/(VI) OK Cancel Help

Date/Time run: 05/14/20 06:53:26 Temperature: (A) bias.dat (active) 1.0 (15.915K, 1.0000) 0.8 Trace Color Trace Name Y1 X Values 15.915K CURSOR 12 ABS(V[VO)W/V) 0.9999 0. Center Frequency in Hertz: 0.2 fo = 15.915 kHz 10KHz 20KHZ 30KHz 40KHz SOKHz OHz ABS (V (Vo) /V(VL)) Date: May 14, 2020 Frequency Page 1 Time: 07:02:13 Bode Magnitude plot obtained using PSPICE

C) From other magnitude response plot we can say the given circuit forms the BAND-PASS FILTER.

IC1-bias Profile: Date/Time run: 05/14/20 06:53:26 Temperature: 27.0 (A) bias.dat (active) 1.0 0.8 (14.952K, 707.109m) (16.941K, 707.102m At fc1= 14.952kHz At fc2=16.941 kHz 0.6 (Gain becomes 0.707times of passband Gain at lower and upper cut-off frequencies 0.4 12.000KHz 14.000KHZ 16.000KHz 18.000KHZ 19.753KHZ 0.2 10.000KHz ABS (V (Vo)/V(Vi)) Date: May 14, 2020 Frequency Page 1 Time: 07:15:00 Bandwidth (in kHz) = fc2 -fc1 = (16.941kHz - 14.952 kHz) = 1.989 kHz Lower and Upper cutoff frequencies obtained using PSPICE.

Quantities In Hertz: As obtained from PSPICE Simulation - Center frequency (fo) = 15.915 kHz. Lower Cut-off frequency fc1= 14.952 kHz Upper Cut-off frequency fc2 = 16.941 kHz Bandwidth (B.W) = fc2-fc1= 1.989 kHz Quantities In rad/sec - Resonant Frequency in (krad/sec) Wo = 211 * fo = 100 krad/sec Lower Cut-off frequency in (krad/sec) wc1= ( 211 * fc1) = 93.95 krad/sec Upper Cut-off frequency in (krad/sec) wc2 = ( 211 * fc2) = 106.45 krad/sec Bandwidth in (krad/sec.) (B.W) = 2 * B.W(kHz) = 12.5 krad/sec Quality factor (Q) = Center or resonant frequency (fo) Bandwidth (B.W) Q = 15.915 kHz ( 1.989 kHz) Q = 8 Answer.