Question

Problem 4 Find the voltages across each of the capacitance in the circuit below 60 μ 40 μ.F

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Answer 1

For a given ckt simplified ckt is, 60 mu F are in series Therefore C_eq1 = 60 mu F times 30 mu F/ 60 mu f + 30 m F = 20 mu F Now 20 mu F and C_eq1 vare in parallel Therefore 20 mu F // 20 mu F = 40 mu F Therefore ckt becomes, Therefore across 40 muF in V_40 mu F = V_1 = 40 mu F/ 40 mu F + 40 mu F times 60 = 30v Now, we have another simplified ckt is Therefore V_2 = 30v and voltage across 60 mu F and 30 mu F is also 30v Therefore another simplified ckt is, Therefore V_3 = 30 mu F/60 mu F + 30 mu F times 30 = 10 v Therefore V_4 = 30 - 10 = 20v

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