Question

4. In the capacitor circuit shown below, what is (A) the equivalent capacitance?i) Start by two 2 μ F capacitors in series, ii) then combine result with the 5 μF capacitor in What is the charge on each capacitor? i) Start by determining the charge on the pacitor. ii) Then note that each parallel branch has 12 V because they are llel. (B) entire equivalent ca connected to the same battery, use that to determine the charge on each branch. ii) Each of the μ F capacitors has the same complete charge of that entire branch of the circuit. (p 473) ral 2 2uF 12V Cca 12V 12V 5. For the two charges shown below, find the locations (other than infinity) where the potential is zero. (p. 467) 2-х -3 HC

Answer 1

when capacitors are parallel then they are simply added to get equivalent capacitance.

So equivalent Capacitor = 6 mu F change on 6 mu F = C middot V = 6 times 12 = 72 mu C Across 5 mu F & 1 mu F, the voltage = 12 V So, charge across 5 mu F = 5 times 12 = 60 mu C charge across 1 mu F = 1 times 12 = 12 mu F Since 2 mu F are in series, so on both 2 mu F capacitance charge will be 12 mu F