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(13%) Problem 6: Consider an appliance that consumes 4.75 kW.h of energy per day. > A 50% Part (a) What is the average power

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given - 14.75 Kw ph means - 1175kw. + - hour op in watt - 11175x10 = 4750 Watt as we kioo that. & Watt - 1 Jove / sea P = = E

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