Homework Answers
Given
mass of K2CO3 = 0.485g
number of moles of K2CO3 = Weight / Molar mass = 0.485g / 138.205 g/mol = 0.0035
from the reaction,
1 mole of K2CO3 gives 2 moles of KCl
then 0.0035 moles of K2CO3 gives (2 * 0.00350) = 0.00701 moles of KCl
therefore weigth of KCl formed = number of moles * molar mass of KCl = 0.00701 * 74.5513 = 0.5232gr.
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