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Problem 8(6.25points) Four ions of equal magnitude charge, +Q are arranged on two opposite corners of a square and -Qon the other two opposite corners, with sides of length d. What is the net electric field at the center of the square? kQ2 d2 e electric field is zero -4ko2 2d2 -4ko2 d2 9.
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Answer #1

Field due to two positive +Q at opposite corners will be zero at the center and similarly field due to two negative -Q charges will be zero at the center. So net field is zero at center. Hence the correct option is C.

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