Solution :
=> Answer :- The confidence interval is (0.625 , 0.803)
Given that x = 50, n = 70
=> proportion p = x/n
= 50/70
= 0.7143
= 0.714 (rounded)
=> q = 1 - p = 0.286
=> for 90% confidence interval, Z = 1.645
=> A 90% confidence interval of the population proportion is
=> p +/- Z*sqrt(p*q/n)
=> 0.714 +/- 1.645*sqrt(0.714*0.286/70)
=> (0.6252 , 0.8028)
=> (0.625 , 0.803) (rounded)
====================================================
Solution :
Given that n = 246, x = 105
(a)
=> The point estimate for the proportion of cell phone owners
aged 18 - 24 who have an android phone is
=> p = x/n
= 105/246
= 0.4268
= 0.427 (rounded)
Use the given data to construct a 90% confidence interval for the population proportion p. x=50,...
stion 14 of 18 (1 point) Attempt 1 of Unlimited View question in a popun iart phone: Among 249 cell phone owners aged 18-24 surveyed, 108 said their phone was an Android phone. rform the following. Part 1 of 3 (a) Find a point estimate for the proportion of cell phone owners aged 18-24 who have an Android phone. Round the answer to at least three decimal places. The point estimate for the proportion of cell phone owners aged 18...
Smart phone: Among 249 cell phone owners aged 18-24 surveyed, 108 said their phone was an Android phone. Perform the following. Part: 0/3 Part 1 of 3 (a) Find a point estimate for the proportion of cell phone owners aged 18-24 who have an Android phone. Round the answer to at least three decimal places. The point estimate for the proportion of cell phone owners aged 18 - 24 who have an Android phone is
MATH Hosted by ALEKS Corp 8.3 Homework Previous 2 3 4 5 6 7 8 9 10 Next Question 2 of 10 (1 point) View problem in a pop-up 8.3 Section Exercise 19 (calc) Smart phone: Among 248 cell phone owners aged 18-24 surveyed, 104 said their phone was an Android phone. Chec S Guide Part 1 Find a point estimate for the proportion of cell phone owners aged 18-24 who have an Android phone. Round the answer to three...
Part 1 Find a point estimate for the preporties of eell pheae omers aged 18-24 wbe have an Andreid phese. Reead the answer to three declimal places The point estimate for the phone is0, 335 propertien of cell phose owers aged 19-34 bo have an Android Part 2 Construct a 99.9% confidence interval for the propertiea of eell pho" "am agd isla wb. have an Andreid phone. Round the swiwer to three decimal places A 99.9% conSlesee interval for the...
Use the given data to construct a confidence interval for the population proportion p of the requested level. x= 49, n= 68, confidence level 99% Round the answer to at least three decimal places. The confidence interval is
Use the given data to construct a confidence interval for the population proportion p of the requested level. x=54, n=71, confidence level 99.8% Round the answer to at least three decimal places. The confidence interval is C D .
Among 246 cell phone owners age 18 to 24 surveyed 105 said their
phone was an android phone.
Assume that an advertisement playing at 33% of cell phone
owners aged 18 to 24 have an android phone does the confidence
interval contradict this claim?
The confidence interval (does/does not) contradict the claim,
because 0.33 (is,is not) contained in the confidence
interval.
LEOUIZFdohuwEZEC efavorites here, select then , and drag to the Favorites Bar folder. Or import from another browser. Import...
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Round to three decimal palces Of 98 adults selected random from one town, 68 have health insurance Find a 90% confidence interval adults in he own who have heal e proportion on r e a ns rance 0585 < p < 0 802 B. 0.617<p<0.770 A. C. 0603 p<0.785 D. 0.574p<0.814
Use the given degree of confidence and sample data to...
A sociologist wants to construct a 90% confidence interval for the proportion of children aged 8-10 living in New York who own a cell phone. A survey by the National Consumers League taken in 2012 estimates the nationwide proportion to be 0.42. Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.02?
A sociologist wants to construct a 90% confidence interval for the proportion of children aged 8-10 living in New York who own a cell phone. A survey by the National Consumers League taken in 2012 estimates the nationwide proportion to be 0.42. Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.02?