Calculate E for the following electrochemical cell at 25°C Cu|Cu2+(0.01M) || Zn2+(0.05M)]Zn Select one: a. -0.977V...

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Answer 1

Answer #1

Date................. E = -0.34 Anode :- culs) Cult (aq) + 2€ cathode : Zn2+ (aq) + 2e zncs) E = -0.76 V overall Run - Cu(s)

Answer 2

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