Question

certain material has an index of refraction of 1.4 in air.calculate its polarizing angle

Answer 1

$\theta_B=\tan^{-1}{\frac{\mu_2}{\mu_1}}=\tan^{-1}{1.4}=0.95\,rad=54.43^0$

Answer 2

Polarizibg angle = tan^-1(refractive index) = 54.46

Answer 3

Polarizing angle = tan^-1 (n2/n1

= tan^-1 (1.4

= 54.46 degree

Answer 4

$\theta_\mathrm B = \arctan \left( \frac{n_2}{n_1} \right),$  where n₁ is the refractive index of the initial medium through which the light propagates (the "incident medium"), and n₂ is the index of the other medium.

index of refraction of air , n1 = 1.000277

and n2 is given = 1.4

so $\Theta$_B = 54.45⁰