Question

Calculate the KM and Vmax for the enzymatic reaction graphed below.

Wn [s] 005 006 006 002 001 vfumol/min)

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Answer #1

Vmax is the maximum rate of reaction. It is that point in the y-axis in he graph given, when the enzyme gets saturated (the curve reaches a constant). In the given graph, the corresponding Vmax when the enzyme activity becomes constant is 2umol/min

Vmax = 2 umol/min

Km is the point on x axis at Vmax/2 in y axis. Vmax / 2 = 1. The corresponding point on x axis is 30uM (approximately).

Km = 30 uM

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