Question

of the phase difference in the space below the table. f = 100 Hz At maximum voltage, the current is (circle one): f = 200 Hz At maximum voltage, the current is (circle one): f = 300 Hz At maximum voltage, the current is (circle one): Maximum Minimum Zero and increasing Zero and decreasing Nonzero and increasing Nonzero and decreasing Other Maximum Minimum Zero and increasing Zero and decreasing Nonzero and increasing Konzero and decreasing Other Maximum Minimum Zero and increasing Zero and decreasing Nonzero and increasing conzero and decreasing Other 5.004 Max. voltage (Vmax) 5.016 Max. voltage (Vmax) 5.004 Max. voltage (Vmax) Max, current (Imax) 0.0240$ Max. current (Imax) 0.04603 Max. current (Imax) 0.06862 Xc =Vmax/Imax 208.57 Xo = Vmax/Imax 108.71 Xc = Vmax/Imax 72.92 Calculated: phase difference: Calculated: phase difference: Calculated: phase difference: Current or voltage leads? current Current or voltage leads? current Current or voltage leads? current

calculate phase difference

find the phase difference

Answer 1

Φ is phase difference
phase difference in pure capacitive circuit phase difference But it's not the ideal case ) (900) You need to calculate phase difference is the from plots like in case I) fa 10042 cursunt at T= 0.026 0.0036 Not clear from picture value of nollage at T = 0.026 5.016 Cos wave so if we model this by V= Vo coswe Voltage as max when wt is multiple of 21 (as for now take it 217) and cussent I= To cos (wt+0) then 0.0036 - Imax Cos (0) coso = 0.0036 0.1497 6.02405 and yes d=81640 current leads in capacitive circuit

30 you can calculate phase difference this way. > u Steps find the time at which tollage maximum on your vollage plot. value find corresponding current Say ť ICH) Then cos o ICA) Imax क cos) I (t) Imax it should be arrouard around 80- 850 no- ideally a pure capacitive circuit resistence has 0= 90° and as resistance increases, o reduces