A projectile is projected from the origin with a velocity of 10.0 m/s at an angle...
A projectile is projected from the origin with a velocity of 10.0 m/s at an angle of 30.0 degrees above the horizontal. What is the velocity of the projectile 2.00 seconds later?
| Vx = 8.7 m/s, Vy = -14.6 m/s | |
| Vx = 14.6 m/s, Vy = -5.6 m/s | |
| Vx = -8.7 m/s, Vy = -14.6 m/s | |
| Vx = -14.6 m/s, Vy = 8.7 m/s | |
| Vx = 5.6 m/s, Vy = -14.6 m/s |
Homework Answers
Vx is always constant
Vx = v cos theta
= 10 cos 30
= 8.66 m/s
= 8.7 m/s <===========Answere
option A only matches this
A is correct
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