1)from diagram total electric potential at point P is V=V1+V2
here V1=1/(40)*(q1/r)=9*109*(4.35*10-6/(
((222+642)*10-4)=57.85*103V
V2=1/(40)*(q2/r)=9*109*(6.79*10-6/(
((222+642)*10-4)=90.30*103V
total potential V=57.85*103V+90.30*103V=148.15*103V
2)magnitude of Electric field at origin is E=1/(40)*(q2-q1)/r2
E=9*109*(6.79-4.35)*10-6/(22*10-2)2=453*103N/c
Consider the two charges on the x-axis in the diagram below. Each charge is 22 cm...
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Two point charges are placed on the x axis. Figure 1. The first
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Two charges are located on the x axis: q1 = +5.5C at x1 = +5.4
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