Homework Answers
Given that
initial activity Ao=30 MBq
time t=2.5*years=2.5*365=912.5 days
half life T1/2=15 days
now we find the decay constant
decay constant =0.693/15=0.0462/days
now we find the activity
activity A=Aoe-t
=30*e^-0.0462*912.5
=1.5 MBq
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