Data for the following reaction are given in the table. 2NO(g) + Br2(g)->2NOBr(g)
| Experiment | [NO],M | [Br2],M | Initial rate, M/s |
| 1 | 1.0x10-2 | 2.0 x10-2 | 2.4x10-2 |
| 2 | 4.0x10-2 | 2.0x10-2 | 0.384 |
| 3 | 1.0x10-2 | 5.0x10-2 | 6.0x10-2 |
What is the rate law for this reaction?
b. What is the overall order of the reaction?
c. What is the rate constant for this reaction?
Please find the attachment for detailed calculation.
![0.384 of (NO) [.NO IM [Br2] & MIS II 10x10? 2x102 214x102 2 4.0x10 2 2x10² 3 10x102 SX102 6.00102 ③ Compare 182 concentrating](http://img.homeworklib.com/questions/c772dfa0-2e7c-11eb-99f7-3f3a9f6239d9.png?x-oss-process=image/resize,w_560)
Data for the following reaction are given in the table. 2NO(g) + Br2(g)->2NOBr(g) Experiment [NO],M [Br2],M...
2NO(g) + Br2(g) = 2NOBr(g) Experiment [NO-] (M) [Br2] (M) Initial Rate (M s-1) 1 0.10 0.20 24 2 0.25 0.20 150 3 0.10 0.50 60 4 0.35 0.50 735 1.) Determine the rate law equation for the reaction. 2.) What is the overall order of the reaction? 3.) What are the value and the units of the rate constant, k? 4.) Write the expression to show how is the rate of disappearance of bromine, Br2, related to the rate...
8) The rate law for the following reaction N2O(g) + NO2(g) → 3NO(g) is Rate = k [N2O][NO2]2. Fill in the blank in the table below. Experiment [N2O], M [NO2], M Initial Rate, MS-1 1 0.100 0.100 2.0x10-3 2 0.300 0.100 6.0x10-3 3 0.100 0.200 ? a) 2.0x10−3 Ms−1 b) 4.0x10−3 Ms−1 c) 8.0x10−3 Ms−1 d) 6.0x10-3 Ms-1 e) 1.0x10−2 Ms−1
The rate constant for the second-order reaction: 2NOBr(g) → 2NO(g) + Br2(g) is 0.80/(M · s) at 10°C. Starting with a concentration of 0.86 M, calculate the concentration of NOBr after 59 s.
The rate constant for the second-order reaction: 2NOBr(g) → 2NO(g) + Br2(g) is 0.80/(M · s) at 10°C. Starting with a concentration of 0.86 M, calculate the concentration of NOBr after 89 s. M
Consider the gas-phase reaction between nitric oxide and bromine at 273 ∘C 2NO(g)+Br2(g)→2NOBr(g). The following data for the initial rate of appearance of NOBr were obtained: Experiment [NO](M) [Br2](M) Initial Rate of Appearance of NOBr(M/s) 1 0.10 0.20 24 2 0.25 0.20 150 3 0.10 0.50 60 4 0.35 0.50 735 What is the rate of disappearance of Br2 when [NO]= 8.1×10−2 M and [Br2]= 0.22 M ? Express your answer using two significant figures.
a possible mechanism for the overall reaction is found below:Br2(g)+2NO(g)--->2NOBr(g). step 1: (fast) NO(g)+Br2(g)-->&<---NOBr(g) determine the rate law based on this mechanism. step 2 (slow) NOBr2(g) + NO(g)-->2NOBr(g)
The equilibrium constant for the reaction: 2NO(g) + Br2(g) <----> 2NOBr(g) is Kc = 1.3x10^-2 at 1,000 Ka.) At this temperature, does the equilibrium favor the product or reactants?b.) Calculate Kc for 2NOBr <----> 2NO + Br2c.) Calculate Kc for NOBr <----> NO + 1/2Br2
Consider the reaction: 2NO(g)+Br2(g)⇌2NOBr(g)2NO(g)+Br2(g)⇌2NOBr(g) KpKp=28.4 at 298 KK In a reaction mixture at equilibrium, the partial pressure of NONO is 116 torr and that of Br2Br2 is 132 torr. What is the partial pressure of NOBr in this mixture? Answer in 3 significant figures
A student ran the following reaction in the laboratory at 312 K: 2NO(g) + Br2(g) 2NOBr(g) When he introduced NO(g) and Br2(g) into a 1.00 L evacuated container, so that the initial partial pressure of NO was 1.07 atm and the initial partial pressure of Br2 was 0.448 atm, he found that the equilibrium partial pressure of Br2 was 0.189 atm. Calculate the equilibrium constant, Kp, she obtained for this reaction. Kp =
for the reaction 2NOBr(g)---- 2NO(g)+Br2(g) the rate
of the reaction -2.3 mol NOBr/L/h when the initial NOBr
concentration was 6.2 mol NoBr/L. what is the rate constant of the
reaction.
Please help:)
52. For the reachon ZNO Brly) - 2Noig) + Brela) the rate of the reaction was -23 mol NoBrilh when the inihol NOBY Coventration was 2 mol NOBYL Wat is the rate constant of the reaction?