The contingency table is given as follows:
|
Observed frequency |
||||
|
National News |
Sports |
Comics |
Total |
|
|
City |
32 |
30 |
28 |
90 |
|
Suburb |
74 |
64 |
42 |
180 |
|
Rural |
110 |
25 |
15 |
150 |
|
Total |
216 |
119 |
85 |
420 |
Null Hypothesis: Ho – the type of community and section of newspaper are independent
Alternative hypothesis: H1 – the type of community and section of newspaper are dependent
Determining test statistics
χ2test = Σ[(f0 – fe)2/fe]
Where,
f0 = observed frequency of the category
fe = expected frequency of the category
The expected frequency of the category is calculated as follows:
fe = (∑rf0)(∑cf0)/(n)
∑rf0 = total observed frequency of respective row
∑cf0 = total observed frequency of respective column
n = total number of observation = 420
Expected frequency for city resident and national news subscriber category = (90)(216)/(420) = 46.29
Similarly expected frequencies for the remaining category are as follows:
|
Expected frequency |
||||
|
National News |
Sports |
Comics |
Total |
|
|
City |
46.29 |
25.50 |
18.21 |
90 |
|
Suburb |
92.57 |
51.00 |
36.43 |
180 |
|
Rural |
77.14 |
42.50 |
30.36 |
150 |
|
Total |
216 |
119 |
85 |
420 |
Contribution of category to Chi-square test is calculated as follows:
Contribution = (f0 – fe)2/fe
For City and national news category the contribution is calculated as follows:
Contribution = (32 – 46.29)2/(46.29) = 4.41
Similarly, contributions of other categories are obtained as follows:
|
Contribution |
||||
|
National News |
Sports |
Comics |
Total |
|
|
City |
4.41 |
0.79 |
5.26 |
10.46 |
|
Suburb |
3.73 |
3.31 |
0.85 |
7.89 |
|
Rural |
13.99 |
7.21 |
7.77 |
28.97 |
|
Total |
22.13 |
11.31 |
13.88 |
47.32 |
test statistics
χ2test = Σ[(f0 – fe)2/fe]
Value of test statistics = χ2test = 47.32
Critical value
Degree of freedom = (r – 1)(c – 1) = (3 – 1)(3 – 1) = 4
Significance level = 1 – 0.95 = 0.05
From table of Chi-square, χ2critical = 9.488
Using the critical value approach, the decision rule is to reject the null hypothesis if χ2test >= χ2critical
Since, χ2test (47.32) >= χ2critical (9.488), we reject null hypothesis that the type of community and the section of the newspaper subscriber reads are independent at a = 0.05.
From table, χ2test = 60.44 and degree of freedom = 4, p-value < 0.005
Since p-value < a (0.05), reject null hypothesis.
Thus, there is sufficient data to conclude that there is relationship between the type of community and the section of the newspaper subscriber reads at 95% confidence level.
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