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Problem 1 The director of Gainesville Sun newspaper is studying the relationship between the type of com- munity in which a s

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Answer #1

The contingency table is given as follows:

Observed frequency

National News

Sports

Comics

Total

City

32

30

28

90

Suburb

74

64

42

180

Rural

110

25

15

150

Total

216

119

85

420

Null Hypothesis: Ho – the type of community and section of newspaper are independent

Alternative hypothesis: H1 – the type of community and section of newspaper are dependent

Determining test statistics  

χ2test = Σ[(f0 – fe)2/fe]

Where,

f0 = observed frequency of the category

fe = expected frequency of the category

The expected frequency of the category is calculated as follows:

fe = (∑rf0)(∑cf0)/(n)

∑rf0 = total observed frequency of respective row

∑cf0 = total observed frequency of respective column

n = total number of observation = 420

Expected frequency for city resident and national news subscriber category = (90)(216)/(420) = 46.29

Similarly expected frequencies for the remaining category are as follows:

Expected frequency

National News

Sports

Comics

Total

City

46.29

25.50

18.21

90

Suburb

92.57

51.00

36.43

180

Rural

77.14

42.50

30.36

150

Total

216

119

85

420

Contribution of category to Chi-square test is calculated as follows:

Contribution = (f0 – fe)2/fe

For City and national news category the contribution is calculated as follows:

Contribution = (32 – 46.29)2/(46.29) = 4.41

Similarly, contributions of other categories are obtained as follows:

Contribution

National News

Sports

Comics

Total

City

4.41

0.79

5.26

10.46

Suburb

3.73

3.31

0.85

7.89

Rural

13.99

7.21

7.77

28.97

Total

22.13

11.31

13.88

47.32

test statistics  

χ2test = Σ[(f0 – fe)2/fe]

Value of test statistics = χ2test = 47.32

Critical value

Degree of freedom = (r – 1)(c – 1) = (3 – 1)(3 – 1) = 4

Significance level = 1 – 0.95 = 0.05

From table of Chi-square, χ2critical = 9.488

Using the critical value approach, the decision rule is to reject the null hypothesis if χ2test >= χ2critical

Since, χ2test (47.32) >= χ2critical (9.488), we reject null hypothesis that the type of community and the section of the newspaper subscriber reads are independent at a = 0.05.

From table, χ2test = 60.44 and degree of freedom = 4, p-value < 0.005

Since p-value < a (0.05), reject null hypothesis.

Thus, there is sufficient data to conclude that there is relationship between the type of community and the section of the newspaper subscriber reads at 95% confidence level.

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