Question

Incorrect Question 9 0/1 pts What is the smallest resistance you can obtain by connecting a 8.752, a 10.2 and a 178 resistor together? (Assume 3 significant digits and units of Ohms). 0.218 Which gives you a smaller resistance, resistors in parallel or in series? Show transcribed image text Expert Answer

okay so I understand I have to take 1/8.75+1/10.2+1/178.

When I add these numbers I get 0.2179..

My question is how did they get 4.588.

Please show math to help me see how they got this number

Answer 1

You have said that you have understood that to get the minimum resistance you need to connect them parallelly. So I would do only the calculation part.

in tam R3 3 equivalent to if, R, R₂ & R3 are in parallel combination & if Reg in their equivalent repintance, then Rakit ky+ R = (3.75 + Ton2 + 1+8) = 0.2179429 2 -> Ree = 0.2179 2 A Req moB R = 8.75 2 3.75 27 similarly, I = 10.2 & 4 8 118 2 Then we have added them thers to get R + - + - 178 inverting both "sider of the 0.2179 ł equation | - Reg ~ 4.588 2

As you can see, 0.2179 is the value of the inverse of R_eq . So we need to invert 0.2179 to get the value of R_eq .

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