Question

128. 3(20 – 1°(2)(x + 3)/2 + (2x – 1)* ( 1 ) (x + 3)-1/2

PLEASE SHOW ME HOW TO FACTOR THIS PLEASE AND THANK YOU!

Answer 1

We need to find how we can find the factor? Factors means reduce the equation to get the values of variables(x,y,z,..... ) . I used the factorisation method in this question. Hope You understand better.
Solution : equation given is, 3620-1920x32x+3)2 + (2x-1)3 (+)(x+3) '/2 We need to facto size this equation. Let me explain this in the following steps: Stebin Take out (x+3)'12 courmon from - the above equation then we get, (oe+3)2 { 3(2x-13268) + (2x+13 (1) atas} Step – Tgain take cox-132 common ai út .- has least power, stuen we get, («+3) 12 (22-1246 + (Dx-1) (+) (kto) I I ? iwe divide the above the main ûn parts I, I and I respectively. Step 3 solue part III separatily and then conline with other parts, 40+ 6+ (2x+16) Galtz) = 6+ @ x-1) = 662) Coet3)+2x 2 (+3) Tacx+3) - 12(x+3) + 2x1 - 100+ 36 +2x-1 (x+3) Dlx+3)

TU) = 140 + 35 e colt 3) Combine this Till paret with parts (I) and (II). = (x+3) 42 (2x+133 (14x +35) Hint: gupta {Qx1) (ex-1)(14x +35) CRA33'72 fi: (x+3) a catb)!l2 (8+3)/2 2 (2+3) = (x+3)/2 (x+3) 1/27 Step 54 Requireed factors of ttie equation are :- (2x-1)( &H-116142+ 35) Q (x+3)112
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