Question

A 0.50-kg block attached to an ideal spring with a spring constant of 80 N/m oscillates on a horizontal frictionless surface. The total mechanical energy is 0.12 J. The greatest speed of the block is:

Answer 1

Total mechanical energy of a block moving in an SHM is

$E = 0.5m\omega ^{2}A^{2}$

$0.12 = 0.5*0.5*\omega ^{2}A^{2}$

Maximum speeds is given by

$v_{max}=(\omega*A)$

$0.12 = 0.25*v_{max}^{2}$

$v_{max}= 0.6928 m/s$