Question

Exam No. 2 (final) sestion No. 19.Ciceye A telemarketing finn in Miami uses a device that dials residential telephone numbers in the city at random. Of the first 220 numbers dialed, 51% were unlisted. This is not surprising because 48% of all Miami residential phones are unlisted. (A) The 48% is a statistic, and the 51 is a parameter (B) Both the 485 and the 515 are statistics (C) The 485 is a parameter, and the 515 is a statistic (D) Both the 485 and the 51% are parameters (E) None of the above is necessarily true (F) Not enough iaformation to answer the question Question No. 20.Cenye Find the proportion of observations from a standard normal distribution curve that satisfies Descore: -0.1 < <0.7 (A) 0.3 (B) 0.12 (C) 0.7 (D) 0.23 (E) 0.21 (F) 0.37 (G) None of the above (your answer: (H) Not enough information to answer the question

Answer 1

$\dpi{100} \mathbf{Solution}$

$\dpi{100} {\color{blue} \mathbf{Question\;No.\;19}}$

$\dpi{100} \mathbf{Answer}:\;{\color{red} \mathbf{(C)}}\;\mathbf{The\; 48\%\; is \;a \;parameter, \;and\; the\; 51\%\; is \;a\; statistic }$

$\dpi{100} {\color{blue} \mathbf{Question\;No.\;20}}$

$\dpi{100} \mathbf{Answer}:\;\mathbf{{\color{red} \mathbf{(A)}}\;0.3}$

$\dpi{100} P(-0.1<z<0.7)=?$

$\dpi{100} \Rightarrow P(z<0.7)-P(z<-0.1)$

$\dpi{100} \mathbf{Refer \; Z-table\; to\; find\; the\;probability }$

$\dpi{100} \Rightarrow 0.7580-0.4602$

$\dpi{100} \Rightarrow 0.2978$

$\dpi{100} \approx \mathbf{{\color{Red} 0.3}}$