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can you do Part B with the new q2 value. i know the correct answer but can you show how you get it bc i keep getting 20.7 degrees below the axis. thanks

<Homework-1 Practice Problem 17.04 - Enhanced - with Feedback 2 of 6 • Comple Review I Constant Previous Answers Now we will
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งา ) 6.675 N (-x) (9x10²) (3x 4 )x1012 (0.4072 F,= (4x10 (2x4) *10-12 (0.70 0.288 N re 0.288 X 0.4 0.2304 N (+) = کی ۵۰ Fiy

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