Calculate the pH of a rain cloud that has equilibrated with 1.0 ppm by volume SO_2.

Question

Question

science chemistry

Answer 1

Answer #1

P_SO2 = (1 atm)(1 x 10^-6) = 1 x 10^-6 atm

[H₂SO₃] = K_H·P_SO2 = (1.0 M/atm)(1 x 10^-6 atm) =1 x 10^-6 M

Reaction: H₂SO₃ ↔ H⁺ + HSO₃^- Ka₁ = 0.017

Ka1 = 0.017 = [H⁺+ ][HSO₃^- ] / [H₂SO₃] = [H+ ]² / 1 x 10-6

[H+ ] = [(0.017)(1 x 10-6)]0.5 = 4.123 x 10-4 M

pH = 3.38

Answer 2

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