



Question 1. (15 points) Consider the following LL (1) grammar with starting symbol S s→(ST) F...
2. Consider the following context free grammar with terminals (), +, id, num, and starting symbol S. S (ST) F-id Fnum a. Compute the first and follow set of all non-terminals (use recursion or iteration, show all the steps) Show step-by-step (the parsing tree) how the following program is parsed: (num+num+id)) b.
Consider the following LL(1) grammar with terminals (, ), +, id,
num, and starting symbol S.
Compute the first and follow set of all the nonterminals.
S → (ST) F→id
(10] Eliminate left recursion from the grammar A Ba |Aa c B Bb | Ab 1 d A Ad IB A BA ASJAE Consider the following grammar G: S'S S (S)S|e fa) (10] Construct the collection of the sets of LR(0) items (b) [5] When constructing the action table of SLR parser of G what are the rules to determine the parsing actions? That is, what is the rule for a shift action at state /? What is the rule...
Name: 3. (10 points) Given grammar: <program> → <stmts> Page: 2 <term> → <var> 1 const 1), write down derivation of: c-5+a 2) What are terminals and what are non-terminals in the grammar? Show a complete parse, including the parse stack contents, input string, and action for the string: id - id + id, using the grammar and parse table below. (10 points) 4. Grammar State id S4 4. T F 5. F (E) R2 S7 R4 R4 R2İR2 Parse...
Consider the following grammar: (//some alternative rules are listed on separate lines without using symbol |): stmt −> assignment −> subr call assignment −> id := expr subr call −> id ( arg list ) expr −> primary expr tail expr tail −> op expr −> ε primary −> id −> subr call −> ( expr ) op −> + | - | * | / arg list −> expr args tail args tail −> , arg list −> ε...
For the following grammar (7 points) 1. B - Ba|A S - ABb A - Aba |A to find a grammar without A productions that generates the same language, we first identify non-terminals that drive A. These non-terminals are: A and B. Then from S - ABb, we construct S from A - Aba, we construct A - from B - Ba, we construct B - So, the grammar without A that generates the same language is:
Please help me with the coding for LL(1)!!
The given grammar was:
P → PL | L
L → N; | M; | C
N → print E
M → print "W"
W → TW | ε
C → if E {P} | if E {P} else {P}
E → (EOE) | V (note: this has a variable O)
O → + | - | * V → 0 | 1 | 2 | 3 (note: this has a terminal...
Given the following grammar, FIRST and FOLLOW sets and LL Parser table, trace the parse of the string “fd xcor + ycor rt ycor” and draw the parse tree. FIRST(S) = FIRST(B) = FIRST(D) = { fd, rt } FIRST(A) = { fd, rt, ε } FIRST(E) = { xcor, ycor } FIRST(F) = { +, -, ε } FOLLOW(S) = { $ } S --> BA FOLLOW(A) = { $ } A --> BA | ε FOLLOW(B) = {...
10 pt) Consider the following grammar where S is the start variable » terminals: x, y, z,t,,* non-terminals: El T, F, V * start symbol: E production rules (a) (4 pt) What is the associativity of the operators+,, * and/ explain why. (b) (3 pt) What is the precedence of , and / explain why (c) (3 pt) Given a parse tree F * T 2 2 Explain how the value of the string is generated