4.
= electric flux through a closed surface = 2.5 Nm2/C
Q = charge enclosed within closed surface = ?
Using gauss's law
= Q/
inserting the values
2.5 = Q/(8.85 x 10-12)
Q = 2.2 x 10-11 C
5.
= net electric flux through the surface
Q = net charge enclosed within closed surface = 5.5 x 10-6 C
Using gauss's law
= Q/
inserting the values
= (5.5 x 10-6)/(8.85 x 10-12)
= 6.2 x 105 Nm2/C
Please answer 4 and 5 fast thanks N-mWhat quantity f ye The electric flux through a...
A closed surface encloses a net charge of 5.5x10^-6 C. What is the net electric flux through the surface?
If the electric flux through a closed surface is determined to be 2.30 N⋅m2/C , how much charge is enclosed by the surface?
12 points OSUniPhys1 23 2 WA014 what is the net electric flux through a closed surface that encloses the following four charges: q1- 2.50 pC, o:" +7.65 μC q3--22.51 C ande.-+45.0c, N m2/c Additional Materials 華eBook
Electric Fields, Flux and Gauss' Law.
Help me please to answer on these questions. Thank you!
is the net electric flux through the closed surface in each case shown below? Assume that 5 lines leave a charge of +q or terminate on a charge of -q. (Assume that all of the surfaces are three-dimensional.) Use the net number of field lines leaving the 4. What suirtuce as a meusure of flux. Explain in the spuces below how you arrived at...
Part A.) The electric flux through a spherical surface is
4.0\times 10^4~\text{N}\cdot\text{m}^2/\text{C}4.0×10 4 N⋅m 2
/C. What is the net charge enclosed by the surface?
Part B.) The electric field 10.0 cm from the surface of a copper
ball of radius 5.0 cm is directed toward the ball’s center and has
magnitude 9.0*10^2N/C. How much charge is on the surface of the
ball?
Select the correct answer
a.) 2.2*10^{-10} . b.)-1.25*10^{-10} . c.)-1.0* 10^{-9} .
d.)-4.5* 10^{-10) ....
4) 18. Find the net electric flux through (a) the closed spherical surface in a uniform electric field shown, and (b) the closed cylindrical surface shown. (c) What can you conclude about the charges, if any, inside the cylindrical surface? 2R
Gauss’ law states that the electric flux through a closed mathematical surface is proportional to the total charge enclosed by that surface, ΦE∝qenc. The symbol ΦE represents the process of performing an integral of the electric field over the closed surface, ΦE=∮E→⋅dA→. The full mathematical statement of Gauss’s law is: Using the slider control in the simulation, move the center of the surface to the point x = 5 R / 4 and y = 0 . What is the...
Please ANSWER all parts of this question. Thanks for your
help.
Determine whether each statement below about flux is true or false. The electric flux is calculated as a cross product The total electric flux for three point charges with +3Q, +4Q, and -6Q has a negative value. The total electric flux through a closed surface depends on all charges within and outside the surface. Submit Answer Tries 0/2 -d The figure above shows a very large nonconducting plate that...
4. a- A Gaussian sphere with radius 1.20 m encloses a point charge Q1 = 2.20×10–6 C at the spherical center. The electric flux through the spherical surface is measured to be 1. Now Q1 is removed, and another point charge Q2 = –8.80×10–6 C is placed at the spherical center. The electric flux through the spherical surface is then measured to be 2. What is 2/1? b- A Gaussian sphere with radius 1.20 m encloses a point charge Q1...
4 a) A constant electric field of value 25.000 N/C is running through a rectangular pipe, whose end is cut off at a 35 TO THE SURFACE of the rectangle. Determine the net flux going through the end of the pipe. EZ, E 40 cm 2535 Net Flux 4 b) A box contains two charges: +12 nC and -4 nC of charge. What is the net flux which comes either out from or into the box. Note, a reasonable value...