Question

Solve only for point C and use Newmark Chart method.

Ilyur 10. TU 10.17 Refer to Figure 10.47. A flexible rectangular area is subjected to a uniformly distributed load of g = 330 kN/m². Determine the increase in vertical stress, Ao,, at a depth of z = 6 m under points A, B, and C. - 18 m- 7.2 m 9 m 3.6 m ---- q=330 kN/m2

Answer 1

comment if any doubt regarding the problem thank you

Ibu? Given - 8m - Depth at which stren Sumo 11-7203 required (Z) = 6m 0 3.6m @ q=330kN/m² we can find the vertical stress at al - by using un ration in Newmark's Chart from un chart Consider 'u' rectangles 1,27 Fol 0 - 1 4 I. - 0.176 na Blz: 5.) 0,91 FOI COD mo 1008 -187 I, = 0.18886 n= 5.4 > 0.9 Fr , m= 72/6 = 1.2 z a 1.2 no B12 => 3.6 -0.6 13 = 0.1418 FB? , M = 4z -> 1078541.82 z Iy=0.15136 ni » 365.06! we know that wing Newmarks chart 124 = (1, 2) + (129)+ (1:0) + (Jy wj z DV ( I, + 12+ 33+ Jy) =) 330(0.17670-1888670.1418 - 0.6580 x 330 Az = 217.146 kn/m² +0.15736