Question

Problem 2 Determine the potential of the same for the electric field spherical shell by using the result [7 marks Determine the electric field inside and outside a uniformly charged spher- ical shell of radius R and total charge q. 5 marks]

Answer 1

® here I have solved and part (1) because by using Electric field we can determine Electric potential . The charge distribution is spherically symmetric, with a surface charge density o= 9 = 9/ana? where A is surface area of sphere. The Electric field must be radially symmetric & directed outward here we have to find (W Electric field inside i.e. realik Electric field outside ierna. Electric field for Case i rcq leniform spherical shell We choose our Gaussian surface to be sphere of radius rça, ar shown in fig. The charge enclosed by Gaussian surface genc=0 i all the charge is located on all Surface the surface of shell, ther from Gauss's law pe= Genel tale conclude E = o rea Case 2 ] ">,9 since the radius of the " Gaussian & sphere" is greater than ? Gaussian radiour of the spherical shell . of surface all the charge enclored, O qenc = 9. Gaussian

Flex through the Gaussian Surface ir Polda = EA = EC45102) by applying Pauss' lace, E = 2 = ker , rya- required 4T1Gor2 +/- E = unGgrr, rygg & Electric potential due to spherical shell tttt from above discussion, we conclude that I ryg UTG12 7777 10 irco Electric potential may be calculated by using Eq VBAVA = Sed Case for rya VR-VA a - seeds Ver - Ves = ago ang dr = 16 (7) [ Ver) - Yo) a ked where we have choosen Vco)= 0 at our reference point on the other hand VB- VA Case

Care (2) for real the potential becomes Vaj - Vccole - dr El far (co n 1 4 TIGO Vea= kel - Erequired)