Question

A package of mass 50 kg is dropped from a helicopter and experiences a drag force of 120 N due to air resistance. Find the resultant force and use it to calculate the acceleration of the package during the fall. Take the acceleration due to gravity as g = 9.81 m s^-2 and give your answer in m s^-2 to 1 decimal place.

Answer:    Answer m s^-2

Answer 1

Solr: Given, Mass (m) - 50kq & Force(P): 120N * Take acceleration due to gravity cg) = 9.81 mlsz => kle know, Hewton's and law, Foet ma by Fact mg-Edrag = mg- Edrag 50 xa 50x73\-|o as 370.5 50 1 3705 500 a = 7.41 ms Acceleration of the package during the fall is (a = 7.42 m3?

Answer 2

Fw = mass x g = 50 kg x 9.81 m s^-2 =  490.5 N

F_w = 490.5n         F_drag = 120n

Resultant force = 490.5n - 120n = 370.5n

acceleration =	force	=	370.5	m s-2  = 7.41m s-2
	mass		50

to 1 decimal place = 7.4m s^-2