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If you have 0.316 m3 of water at 25.0°C and add 0.122 m3 of water at...

If you have 0.316 m3 of water at 25.0°C and add 0.122 m3 of water at 95.0°C, what is the final temperature of the mixture? Use 1000 kg/m3 as the density of water at any temperature.

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Answer #1

Convert temperature t for celsius to kelvin.

Multiply volume of one container by it's temperature(in kelvin) + volume of the other * temperature of the other. Divide all that by combined volume.

(0.316*298+0.122*368)/0.438= 317.49K= 44.49degrees C

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