Question

0.0800 g of a compound with the empirical formula C2H2N is dissolved in 10.00 g benzene. The resulting solution freezes at 5.24°C. Benzene freezes at 5.48°C and has a freezing point depression constant of K - 4.90"C/m. What is the molecular formula of the compound? CHEN CHONA CH N3 OCHEN O CHAN2

Answer 1

w Kups, ky aty - kr. m. i frering point depression Constant, 4.90°c (m. ε 414 Tepune solo) If (sonation) = (5.48-85.24°C 0.24°C. modality of solution, want hoff's factor 1 organi the Compound. OTS m.i 0,24 = 4.90x mxi 10.26 4.90 = 0.04898 m Molality there а go mol of solute dissolved in 1000 4oog g solvent 10.00g benzene mols Compound in Tin means 0.05 X/0 1000 -4 5x10 moles Compoun 11

5.810 mole 0.08 g 1 mol 160.0g/mol 160.0 g/mol. g/mos. (moleculare mass) M compound Now C2H₂N. empirical formula 2 out of eg Hay N4 or C6H63 or This means is the answer. (4 HqN2 Me = 12.0 g/mol MH 1.000 g/mol 16.0 g/mol 2 above out of this the Cg Hg N4 = mentioned formulas [(1248) + (8X16) + (4x14.017 5 (mo) 160.0 g/mol of the Answer- Molecules formula of Compound Cq Hg N4