0.230 g of a compound is dissolved in 10 g of cyclohexane. the solution freezes at 5.12 degrees celcius. calculate the molecular weight of the compound. the freezing point of pure benzene is 5.455 degrees Celsius and the kf = 5.065 degrees Celsius/ m
0.230 g of a compound is dissolved in 10 g of cyclohexane. the solution freezes at...
The freezing point of a solution of 1.104 g of an unknown nonelectrolyte dissolved in 36.81 g of benzene is 1.08°C. Pure benzene freezes at 5.48°C and its Kf value is 5.12°C/m. What is the molecular weight of the compound?
Pure cyclohexane, C6H12, has a freezing point of 6.53 celcius. Its freezing point depression constant is: Kf=20.0 degrees celcius m^-1. A solution was made by taking 10.55g of an unknown nonelectrolyte and dissolving it in 125.0g of cyclohexane. The measured freezing point of the solution was -3.28 degrees Celsius. Calculate the molecular weight of the unknown substance.
A 1.20 g sample of an unknown compound is dissolved in 60.0 g of benzene. The resulting solution freezes at 4.92 degree C. Calculate the molecular weight of the unknown. Pure benzene freezes at 5.45 degree C\ K_f for benzene is 5.12 degree C/m
The freezing point of a solution that contains 1.00 g of an unknown compound, (A), dissolved in 10.0 g of benzene is found to be 2.17 oC. The freezing point of pure benzene is 5.48 oC. The molal freezing point depression constant of benzene is 5.12 oC/molal. What is the molecular weight of the unknown compound?
What is the molar mass of a nonpolar molecular compound if 6.34 g dissolved in 53.4 g benzene begins to freeze at 2.81 °C? The freezing point of pure benzene is 5.50 °C and the freezing point depression constant, Kf, is -5.12 °C/m. A. 2.26 x 10-4 g/mol B. 0.226 g/mol C. 12.1 g/mol D. 226 g/mol
A nonvolatile, non-dissociating solute was dissolved in 12.0 g of benzene (C6H6). The freezing point of the solution was measured as 1.3 °C, while pure benzene freezes at 5.5 °C. If pure benzene has a vapor pressure of 75 torr, what is the vapor pressure of this solution. For benzene, Kf = 5.12 °C/m and Kb = 2.53 °C/m.
A 2.50 g sample of naphthalene, C10H8, was dissolved in 100 g of benzene. What is the freezing point of the solution? The freezing point of pure benzene is 5.45 degrees Celsius; Kf=5.07 degrees Celsius/m. The molar mass of C10H8 is 128.17 g/mol The answer is supposed to be 4.46 degrees Celsius. How did they get there?
What is the freezing point of a solution of 12.8 g of C10H8 dissolved in 500 g of benzene? The normal freezing point of pure benzene is 5.48 oC and its Kf is 5.12 oC/m.
1.0345 g of palmitic acid dissolved in 8.7545 g of stearic acid. Calculate the freezing point of the solution. The molar mass of palmitic acid is 256.48 g/ mol. The molal freezing point constant , Kf for stearic acid is 4.5 degrees C/ m and pure stearic acid freezes at 69.3 degrees Celsius.
please help !
26. The freezing point depression of a solution of 1.45g sample of an unknown nonelectrolyte dissolved in 25.00 mL of benzene(density d=0.879 g/mL) is 1.28°C. Pure benzene has Kf value of 5.12°C/m. What is the molecular weight of the compound? (10 points)