Determine the pH of .17M CH3NH3I

Question

Question

science chemistry

Answer 1

Answer #1

CH₃NH₃I is a salt of weak base CH₃NH₂ and strong acid HI.

pK_b of CH₃NH₂ = 10.66

CH₃NH₃I will hydrolyze in solution and resulting solution will be acidic.

CH₃NH₃I = CH₃NH₃⁺ + I^-

CH₃NH₃⁺ + H₂O = CH₃NH₂ + H₃⁺

pH of such solution = 0.5(pK_w - pK_b - logC)

= 0.5(14 - 10.66 - log 0.17)

= 1.28

Answer 2

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