Let the formula of the metal chloride be MClx
As per Dulong's Petits law,
specific heat*atomic mass of the metal = 25
thus, atomic mass of the metal = 65.79 g/mole
Now, moles of metal in 0.5007 g of it = mass/molar mass = 0.5007/65.79 = 0.0076
mass of Cl in the metal chloride = 1.0586 - 0.5007 = 0.5579
Thus, moles of Cl in the chloride sample = 0.5579/35.5 = 0.0157
Thus, M & Cl are present in the molar ratio of 0.0076:0.0157 = 1:2
Thus, the formula of the compound is MCl2
Now, moles of M in the compound = (1/2)*moles of Cl = (1/2)*0.0157 = 0.00785
Thus, molar mass of M = mass/moles = 0.5007/0.00785 = 63.78 g/mole
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