Question

3m Susand a) A block with a mass of 10.0 kg is AS released from rest at the top of an 1 00.kg inclined track (0 = 30°), at point A, 3.0m above the horizontal (see the figure). The track A to B has a coefficient of kinetic friction of 0.10. The horizontal portion of the track, B to C, is 4.Om long - 4m and is frictionless. At point C, where the horizontal track ends, the block touches the free end of a spring (spring constan a frictionless inclined track (inclined at 20°); the other end of the spring is fixed as shown Find the following (Must be solved using energy considerations): c) The speed of the block at the bottom of the first incline, point B. The speed of the block just before touching the spring, point C. The speed of the block when the spring is compressed by 50.0 cm. What is the work done by gravity on the block from A to B? the free end of a spring (spring constant of 300.N/m), which is!

Answer 1

y f - umy (30* my = sin 20° W SOX Si-20 = 17.1 cm. - of AB being = cm. Patential energy at A- Work done by - Kinstic hergy ant batton B. mgh- fx AB = ţ miz a frietim 12(migh-fXAB) m 2 (lox98x3 -0.10x10x 9.8 x 28 30* 6) jo = 6.97 ms. stered of the block at the battom of the 1st incline is 6.97 m/s. - speed of the block just before touching the spring will be same as 6.97 m/s because as the Be Portion is frictionleys no energy will be lost. - Kinetic fexergy at atentich entry (K.E at 2) - (K. E and P. E at D)= Energy of spring. 1/4 mu? (1/2 mu? t ngh,) = Ź KX² {x10x16.97)?(4x10xV12+1098 x 16+1) = *300*6-532 V. x10x66-97)210x 9.88-171 - { *300XC-532 V = 6.14 ms. & speed of the block is 6. 1 amps when the block is 6. 1 am/s when the spring is Compressed... by 50 m. 7. Work done by granity from A to B is z mgh = (10X9.8* 3) J : 294J.