Question

What are the zeros of f(x) = 2x2 - 2x -220?

Answer 1

Given,

To find the zeros of f(x)

Equate f(x) to 0

$2x^{2}-2x-220=0$

Dividing with 2 on both sides

$x^{2}-x-110=0$

$x^{2}-11x+10x-110=0$

$x(x-11)+10(x-11)=0$

$(x+10)(x-11)=0$

$(x+10)=0,(x-11)=0$

$x=-10,x=11$

$x=-10,11$

Therefore,

The zeros of f(x) are $x=-10,11$