Question

1 Sert9 7Pte A ight spring with spring constant ,30 x 10 N/m hangs from an elevated support. From Rs lower end hangs a second Sght spring, which has spering constant 1.95x10 N/m A 1.50-kg object hangs at rest from the lower end of the second spring. (a) Find the total extension distance of the pair of springs m (b) Find the effective spring constant of the pair of springs as a system. We describe these springs as being in senes Hint: Consider the forces on each spring separately N/m Grade This Show Anse Try Again

Answer 1

Hi,

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PART (a):
We know that, According to Hooke's law, Extension of a spring is given by,

K.

For the first spring, extension is given by,

(1.5 kg x 9.8 m/s2) F тg 1.3х 103 N/m i Кі Кі

10.011307692 m

For the second spring, extension is given by,

(1.5 kg x 9.8 m/s2) 1.95 х 103 N/m F тg Т2 К2 К2

20.007538461538 m

$\therefore$Total extension is given by,

.X r1x2 = 0.011307692 m +0.007538461538 m

X0.0188 m

PART (b):

For series combination of spring, Effective spring constant is given by,

Кi.К? 1300 x 1950 К- Кi+ К. N/m 1300 1950

K780 N/m