Question

Read an integer from user and Write C- program to implement process based on value of num as shown below by using switch statement. num Process 25 ra xyz x + y + z 75 xy + yz xyz 15 r = x + y + z x2 + zy otherwise Give correct input value

Answer 1

CODE:

#include <stdio.h>

int main()
{
int num,r,x=2,y=4,z=6;   
scanf("%d", &num);

switch(num)
{
case 23: r=(x*y*z)/(x+y+z);
break;
case 75: r=((x*y)+(y*z))/(x*y*z);
break;
case 15: r=(x+y+z)+((x*z)+(z*y));
break;
default: r=num;
}

printf("The value of r is: %d", r);
return 0;
}

SCREENSHOT AND EXPLANATION WITH OUTPUT:

{ { 1 #include <stdio.h> 2 3 int main() 4 5 int num,r,x=2, y=4,2=6; // integer variable are declared.. here x ,y and z are assigned random values to perform operations 6 scanf("%d", &num); // reads user input and the value is storedin variable 'num 7 8 switch (num) // switch block 9 10 case 23: r=(x+y+z)/(x+y+z); // if num is 23.. then this case is entered and the expression computed and the value is assigned to 'r' 11 break; // break statement is used to exit out of this Loop 12 case 75: r=((x*y)+(y*z))/(x*y*z); // if num is 75.. then this case is entered 13 break; 14 case 15: r=(x+y+z)+((x*2)+(z*y)); // if num is 15.. then this case is entered 15 break; 16 default: r=num; V/ when num does matches either of the cases, then default is entered and the input value is assigned to 'r' 17 18 19 printf("The value of r is: %d", r); // Finally the value of r is printed on the screen 20 return 0; 21 } 22 input 23 The value of r is: 4 }