Question

C++ Design and implement a program (name it PalindromeInteger), to check if an integer value is a palindrome or not, using 2 methods (reverse and isPalindrome) specified as follows: Method reverse(int number) takes integer number and returns number in reverse order. The method mathematically reverses the number. Method isPalindrome(int number) takes integer number and returns true if the number is palindrome; false otherwise. Use method reverse() to implement method isPalindrome(). Notice that an integer value is palindrome if the value and its reverse are equal. In the main method, prompt the user to enter an integer value and the program should display proper judgment whether the input value is palindrome or not. Document your code and properly label the input prompts and the outputs as shown below. Sample run 1: Entered value: 1234 Judgment: Not palindrome Sample run 2: Entered value: 123321 Judgment: Palindrome Sample run 3: Entered value: 1001 Judgment: Palindrome

Answer 1

#include <iostream>

using namespace std;

/**
 * given a number, return reversed of number
 * @param number 
 * @return 
 */
int reverse(int number) {
    int rev = 0;
    while (number > 0) {
        rev *= 10;
        rev += (number % 10);
        number /= 10;
    }
    return rev;
}

bool isPalindrome(int number) {
    return reverse(number) == number;   // return true if reverse of a number is same as the given number
}

int main() {
    cout << "Enter a number: ";
    int num;
    cin >> num; // read a number from user
    cout << "Entered value: " << num << endl;
    if(isPalindrome(num)) { // if it's a palindrome
        cout << "Judgment: Palindrome" << endl; // then tell user that it's a palindrome
    } else {    // if it's not a palindrome
        cout << "Judgment: Not palindrome" << endl; // then tell user that it's not a palindrome
    }
    return 0;
}