Given that, for AgI, at 25°C, Ksp = 1.5×10-16: From a 1.0×10-6-M NaI solution, precipitation of...

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Given that, for AgI, at 25°C, Ksp = 1.5×10-16: From a 1.0×10-6-M NaI solution, precipitation of...

Given that, for AgI, at 25°C, K_sp = 1.5×10^-16:
From a 1.0×10^-6-M NaI solution, precipitation of AgI just begins at what concentration of added Ag⁺?

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Answer 1

Answer #1

Solubility equilibrium of AgI is

AgI(s) <--------> Ag⁺(aq) + I^-(aq)

K_sp = [Ag⁺][I^-] = 1.5 ×10^-16

substituting given concentration of I^-

[Ag⁺][I^-] = 1.5 ×10^-16 M²

[Ag⁺] × 1.0 ×10^-6M = 1.5 × 10^-16M²

[Ag⁺] = 1.5 × 10^-10M

Therefore,

Concentration of Ag⁺ required to start precipitation of AgI = 1.5 × 10^-10M

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Answer 2

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